216=4x^2+60x+224

Solution for 216=4x^2+60x+224 equation:

216=4x^2+60x+224

We move all terms to the left:

216-(4x^2+60x+224)=0

We get rid of parentheses

-4x^2-60x-224+216=0

We add all the numbers together, and all the variables

-4x^2-60x-8=0

a = -4; b = -60; c = -8;
Δ = b2-4ac
Δ = -602-4·(-4)·(-8)
Δ = 3472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3472}=\sqrt{16*217}=\sqrt{16}*\sqrt{217}=4\sqrt{217}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{217}}{2*-4}=\frac{60-4\sqrt{217}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{217}}{2*-4}=\frac{60+4\sqrt{217}}{-8}
$